Regular expression for only characters a-z, A-Z

/^[a-zA-Z]*$/

Change the * to + if you don't want to allow empty matches.

References:

Character classes ([...]), Anchors (^ and $), Repetition (+, *)

The / are just delimiters, it denotes the start and the end of the regex. One use of this is now you can use modifiers on it.

Piggybacking on what the other answers say, since you don't know how to do them at all, here's an example of how you might do it in JavaScript:

var charactersOnly = "This contains only characters";var nonCharacters = "This has _@#*($()*@#$(*@%^_(#@!$ non-characters";if (charactersOnly.search(/[^a-zA-Z]+/) === -1) {  alert("Only characters");}if (nonCharacters.search(/[^a-zA-Z]+/)) {  alert("There are non characters.");}

The / starting and ending the regular expression signify that it's a regular expression. The search function takes both strings and regexes, so the / are necessary to specify a regex.

From the MDN Docs, the function returns -1 if there is no match.

Also note: that this works for only a-z, A-Z. If there are spaces, it will fail.

/^[a-zA-Z]+$/ 

Off the top of my head.

Edit:

Or if you don't like the weird looking literal syntax you can do it like this

new RegExp("^[a-zA-Z]+$");