What function acts as .SelectMany() in jQuery?

map will flatten native arrays. Therefore, you can write:

$("tr").map(function() { return $(this).children().get(); })

You need to call .get() to return a native array rather than a jQuery object.

This will work on regular objects as well.

var nested = [ [1], [2], [3] ];var flattened = $(nested).map(function() { return this; });

flattened will equal [1, 2, 3].

javascript jquery linq

You want this:

$("tr").map(function() { return $(this).children().get(); });

Live demo: http://jsfiddle.net/8aLFQ/12/

javascript jquery linq

You're going to kick yourself:

$("tr").map(function() { return [ $(this).children() ]; });

It's the simple things in life you treasure. -- Fred Kwan

EDIT:Wow, that will teach me to not to test answers thoroughly.

The manual says that map flattens arrays, so I assumed that it would flatten an array-like object. Nope, you have to explicit convert it, like so:

$("tr").map(function() { return $.makeArray($(this).children()); });

Things should be as simple as possible, but no simpler. -- Albert Einstein

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