How to compare two jsons ignoring order of elements in array properties?

Use JSONAssert

They have a loose assert.

Loose:

JSONAssert.assertEquals(exp, act, false);

Strict:

JSONAssert.assertEquals(exp, act, true);

I don't know if such thing exist, but you can implement it yourself.

var group1 = {    id: 123,    users: [       {id: 234, name: "John"},       {id: 345, name: "Mike"}    ]};var group2 = {    id: 123,    users: [       {id: 345, name: "Mike"},       {id: 234, name: "John"}    ]};function equal(a, b) {    if (typeof a !== typeof b) return false;    if (a.constructor !== b.constructor) return false;    if (a instanceof Array)    {        return arrayEqual(a, b);    }    if(typeof a === "object")    {        return objectEqual(a, b);    }    return a === b;}function objectEqual(a, b) {    for (var x in a)    {         if (a.hasOwnProperty(x))         {             if (!b.hasOwnProperty(x))             {                 return false;             }             if (!equal(a[x], b[x]))             {                 return false;             }         }    }    for (var x in b)    {        if (b.hasOwnProperty(x) && !a.hasOwnProperty(x))        {            return false;        }    }    return true;}function arrayEqual(a, b) {    if (a.length !== b.length)    {        return false;    }    var i = a.length;    while (i--)    {        var j = b.length;        var found = false;        while (!found && j--)        {            if (equal(a[i], b[j])) found = true;        }        if (!found)        {            return false;        }    }    return true;}alert(equal(group1, group2))

You could slice the arrays, sort them by Id then stringify them to JSON and compare the strings. For a lot of members it should work pretty fast. If you duplicate Ids, it will fail because sort will not change the order.