How to replace a JSON value in Play

According to the Play Documentation, JsObjects have a method ++ that will merge two JsObjects. So, when you have your new integer value, you simply need:

val updatedJson = json.as[JsObject] ++ Json.obj("customerId" -> newValue)

As of Play 2.4.x you can use +:

val updatedJson = json.as[JsObject] + ("customerId" -> newValue)

(NOTE: the + method was added already in 2.1.x but adds a duplicate field to the object instead of replacing the existing value in versions prior to 2.4.x)

One approach is, as Marc B says, convert the JSON to something like a case class, manipulate that, and then create a new JSON.

However you can also use JSON 'transformers'. Effectively what you do is build a Reads[SomeThing] object. This object is passed to the transform method which you call on your JSON object. It will change the JSON object and return a Success(result) or Failure(error) where result is the new modified JSON. Here's a (comparatively)very simple example:

using json of format: {key -> value}

def jsonXForm(value: String) = (__ \ "customerId").json.update(  (__ \ "customerId").json.put(JsString(value)))json.transform(jsonXForm(yourNewValue)) match {...}`

There is a decent guide here

Something along the lines of:

val updatedJson = if((request.body \ "customerId").as[Int] == -1){  val newId = JsObject(Seq(("customerId",JsString("ID12345"))))  (request.body ++ newId).as[JsValue]} else request.bodyupdatedJson.validate[Report](Reports.readsWithoutUser).map {  case _: Report =>