Jackson, Retrofit, JodaTime deserialization

First View Analysis:

There are some issues in your code. That your provided time "/Date(1461208761970+0000)/" not looking familiar. You have some code issue also. That your constructor can not talk with joda constructor properly

Root Cause:

Your issue:

com.fasterxml.jackson.databind.JsonMappingException: Class com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer has no default (no arg) constructor

is generates from your code:

 at br.com.soutsapp.user.souts.WCFClientTest.getPaymentHistoryTest(WCFClientTest.java:96)

Issue Analysis:

To deserialize value to org.joda.time.DateTime you have to define @JsonDeserialize because Jackson cannot figure out what method/constructor use from org.joda.time.DateTime to initialize it from a string value.

Solution - 1:

You need to use serialize as well as deserialize. You should check jar availability and should set to reading type as JSON.

You can follow these 3 steps.

1. You need to use serialize as well as deserialize. Your date patter should look like as JsonFormat.

Code will be

@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss")@JsonSerialize(using = DateTimeSerializer.class)@JsonDeserialize(using = DateTimeDeserializer.class)private DateTime paymentDate;

2. Make sure that you have on classpath jackson-datatype-joda.

3. Change SSM configuration to use JSON format by default (indefaultMemcachedClient definition):

   <property name="defaultSerializationType" value="JSON" />

Resource Link:

https://github.com/ragnor/simple-spring-memcached/issues/41

Solution - 2:

You can add another constructor also. That may effect.

 public PaymentHistoryItemApiResult() {        super();   }

Resource Link: Following 2 links containing more error analysis with solution

1. Jackson Exceptions – Problems and Solutions
2. Jackson – JsonMappingException (No serializer found for class)

Another Solution:

If you don't want to use deserialize then you can follow details:

@JsonDeserialize expects a JsonDeserializer with a no-arg constructor. The most recent version of DateTimeDeserializer does not have such a constructor.

If you've fixed the format, ie. yourTimestamp should just be a timestamp, then you could simply register the JodaModule with the ObjectMapper. It will use DateTimeDeserializer internally for DateTime fields. You can get rid of the @JsonDeserialize annotations.

mapper.registerModule(new JodaModule());

You'll need to add the jackson-datatype-joda library.

Resource link:

1. joda.time.DateTime deserialization error

For null value serialization and deserialization

If you don't want to serialize null values, you can use the following setting during serialization:

objectMapper.setSerializationInclusion(Include.NON_NULL);

For deserialization Jackson should ideally be able to handle null values in the serialized output.

Credit goes to @jackall

or you can use annotations also in your class.

@JsonIgnoreProperties(ignoreUnknown = true)@JsonInclude(Include.NON_NULL)

I use my custom deserialize:

@JsonDeserialize(using = MyDateTimeDeserializer.class)private DateTime expiryTimeFirebaseCustomAccessToken;

with class:

import com.fasterxml.jackson.datatype.joda.cfg.FormatConfig;import com.fasterxml.jackson.datatype.joda.cfg.JacksonJodaDateFormat;import com.fasterxml.jackson.datatype.joda.deser.DateTimeDeserializer;import org.joda.time.DateTime;/** * Created by rudi on 3/28/18. */public class MyDateTimeDeserializer extends DateTimeDeserializer {    public MyDateTimeDeserializer() {        super(DateTime.class, FormatConfig.DEFAULT_DATETIME_PARSER);    }    public MyDateTimeDeserializer(Class<?> cls, JacksonJodaDateFormat format) {        super(cls, format);    }}

and it's works for me... Maybe it can contribute

Just use https://github.com/FasterXML/jackson-datatype-joda. It works out of the box and you don't have to use additional annotations to serialize/deserialize datetime into joda time objects.