Python read json from url

To me below code is working- in Python 2.7

import jsonfrom urllib import urlopenurl_address = ['https://api.twitter.com/1.1/statuses/user_timeline.json']for i in url_address:    resp = urlopen(i)    data = json.loads(resp.read())print(data)

Output-

{u'errors': [{u'message': u'Bad Authentication data.', u'code': 215}]}

If you use requests module-

import requestsurl_address = ['https://api.twitter.com/1.1/statuses/user_timeline.json']for i in url_address:    resp = requests.get(i).json()    print resp

Output-

{u'errors': [{u'message': u'Bad Authentication data.', u'code': 215}]}

twitter is returning 400 code(bad request) so exception is firing.you can use try...except in your code sample and read exception body to get response json {"errors":[{"code":215,"message":"Bad Authentication data."}]}

import jsonimport urllib.requestfrom urllib.error import HTTPErrortry:    url_address ='https://api.twitter.com/1.1/statuses/user_timeline.json'    with urllib.request.urlopen(url_address) as url:        data = json.loads(url.read())        print(data)except HTTPError as ex:    print(ex.read())

I prefer aiohttp, it's asynchronous. Last time I checked, urllib was blocking. This means that it will prevent other parts of the script from running while it itself is running. Here's an example for aiohttp:

import aiohttpasync with aiohttp.ClientSession() as session:async with session.get('https://api.github.com/users/mralexgray/repos') as resp:    print(await resp.json())