Sort a array of objects lexicographically based on a nested value
var obj = [...];obj.sort(function(a,b){return a.name.localeCompare(b.name); });Be aware that this will not take capitalisation into account (so it will order all names beginning with capitals before all those beginning with smalls, i.e. "Z" < "a"), so you might find it relevant to add a toUpperCase() in there.
You can make it more generic as well:
function sortFactory(prop) { return function(a,b){ return a[prop].localeCompare(b[prop]); };}obj.sort(sortFactory('name')); // sort by name propertyobj.sort(sortFactory('surname')); // sort by surname propertyAnd even more generic if you pass the comparator to the factory...
This will do it:
arr.sort(function(a, b) { return a.name.localeCompare(b.name);});
Using comparison
arr.sort(function (a, b) {return a.name.toLowerCase() > b.name.toLowerCase()})https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String#Comparing_strings