Generate random float number in given specific range of numbers using Bash

If you have GNU coreutils available, you could go with:

seq 0 .01 1 | shuf | head -n1

Where 0 is the start (inclusive), .01 is the increment, and 1 is the end (inclusive).

linux shell random awk

Without any external utilities, generate random real between 3 and 16.999:

a=3b=17echo "$((a+RANDOM%(b-a))).$((RANDOM%999))"

linux shell random awk

To generate 1 random floating point number between 3 and 17:

$ awk -v min=3 -v max=17 'BEGIN{srand(); print min+rand()*(max-min+1)}'16.4038

To generate 5 random floating point numbers between 3 and 17:

$ awk -v min=3 -v max=17 -v num=5 'BEGIN{srand(); for (i=1;i<=num;i++) print min+rand()*(max-min+1)}'15.10674.792383.0488411.364715.1132

Massage to suit.

CodeHunter