How to pass argument in Expect through the command line in a shell script

If you want to read from arguments, you can achieve this simply by

set username [lindex $argv 0];set password [lindex $argv 1];

And print it

send_user "$username $password"

That script will print

$ ./test.exp user1 pass1user1 pass1

You can use Debug mode

$ ./test.exp -d user1 pass1

A better way might be this:

lassign $argv arg1 arg2 arg3

However, your method should work as well. Check that arg1 is retrieved. For example, with send_user "arg1: $arg1\n".

I like the answer provided with this guide.

It creates a parse argument process.

#process to parse command line arguments into OPTS arrayproc parseargs {argc argv} {    global OPTS    foreach {key val} $argv {        switch -exact -- $key {            "-username"   { set OPTS(username)   $val }            "-password"   { set OPTS(password)   $val }        }    }}parseargs $argc $argv#print out parsed username and password argumentsputs -nonewline "username: $OPTS(username) password: $OPTS(password)"

The above is just a snippet. It's important to read through the guide in full and add sufficient user argument checks.