How compiler like GCC implement acquire/release semantics for std::mutex

Threads are a fairly complicated, low-level feature. Historically, there was no standard C thread functionality, and instead it was done differently on different OS's. Today there is mainly the POSIX threads standard, which has been implemented in Linux and BSD, and now by extension OS X, and there are Windows threads, starting with Win32 and on. Potentially, there could be other systems besides these.

GCC doesn't directly contain a POSIX threads implementation, instead it may be a client of libpthread on a linux system. When you build GCC from source, you have to configure and build separately a number of ancillary libraries, supporting things like big numbers and threads. That is the point at which you select how threading will be done. If you do it the standard way on linux, you will have an implementation of std::thread in terms of pthreads.

On windows, starting with MSVC C++11 compliance, the MSVC devs implemented std::thread in terms of the native windows threads interface.

It's the OS's job to ensure that the concurrency locks provided by their API actually works -- std::thread is meant to be a cross-platform interface to such a primitive.

The situation may be more complicated for more exotic platforms / cross-compiling etc. For instance, in MinGW project (gcc for windows) -- historically, you have the option to build MinGW gcc using either a port of pthreads to windows, or using a native win32 based threading model. If you don't configure this when you build, you may end up with a C++11 compiler which doesn't support std::thread or std::mutex. See this question for more details. MinGW error: ‘thread’ is not a member of ‘std’

Now, to answer your question more directly. When a mutex is engaged, at the lowest level, this involves some call into libpthreads or some win32 API.

pthread_lock_mutex();do_some_stuff();pthread_unlock_mutex();

(The pthread_lock_mutex and pthread_unlock_mutex correspond to the implementations of lock and unlock of std::mutex on your platform, and in idiomatic C++11 code, these are in turn called in the ctor and dtor of std::unique_lock for instance if you are using that.)

Generally, the optimizer cannot reorder these unless it is sure that pthread_lock_mutex() has no side-effects that can change the observable behavior of do_some_stuff().

To my knowledge, the mechanism the compiler has for doing this is ultimately the same as what it uses for estimating the potential side-effects of calls to any other external library.

If there is some resource

int resource;

which is in contention among various threads, it means that there is some function body

void compete_for_resource();

and a function pointer to this is at some earlier point passed to pthread_create... in your program in order to initiate another thread. (This would presumably be in the implementation of the ctor of std::thread.) At this point, the compiler can see that any call into libpthread can potentially call compete_for_resource and touch any memory that that function touches. (From the compiler's point of view libpthread is a black box -- it is some .dll / .so and it can't make assumptions about what exactly it does.)

In particular, the call pthread_lock_mutex(); potentially has side-effects for resource, so it cannot be re-ordered against do_some_stuff().

If you never actually spawn any other threads, then to my knowledge, do_some_stuff(); could be reordered outside of the mutex lock. Since, then libpthread doesn't have any access to resource, it's just a private variable in your source and isn't shared with the external library even indirectly, and the compiler can see that.

All of these questions stem from the rules for compiler reordering. One of the fundamental rules for reordering is that the compiler must prove that the reorder does not change the result of the program. In the case of std::mutex, the exact meaning of that phrase is specified in a block of about 10 pages of legaleese, but the general intuitive sense of "doesn't change the result of the program" holds. If you had a guarantee about which operation came first, according to the specification, no compiler is allowed to reorder in a way which violates that guarantee.

This is why people often claim that a "function call acts as a memory barrier." If the compiler cannot deep-inspect the function, it cannot prove that the function didn't have a hidden barrier or atomic operation inside of it, thus it must treat that function as though it was a barrier.

There is, of course, the case where the compiler can inspect the function, such as the case of inline functions or link time optimizations. In these cases, one cannot rely on a function call to act as a barrier, because the compiler may indeed have enough information to prove the rewrite behaves the same as the original.

In the case of mutexes, even such advanced optimization cannot take place. The only way to reorder around the mutex lock/unlock function calls is to have deep-inspected the functions and proven there are no barriers or atomic operations to deal with. If it can't inspect every sub-call and sub-sub-call of that lock/unlock function, it can't prove it is safe to reorder. If it indeed can do this inspection, it would see that every mutex implementation contains something which cannot be reordered around (indeed, this is part of the definition of a valid mutex implementation). Thus, even in that extreme case, the compiler is still forbidden from optimizing.

EDIT: For completeness, I would like to point out that these rules were introduced in C++11. C++98 and C++03 reordering rules only prohibited changes that affected the result of the current thread. Such a guarantee is not strong enough to develop multithreading primitives like mutexes.

To deal with this, multithreading APIs like pthreads developed their own rules. from the Pthreads specification section 4.11:

Applications shall ensure that access to any memory location by more than one thread of control (threads or processes) is restricted such that no thread of control can read or modify a memory location while another thread of control may be modifying it. Such access is restricted using functions that synchronize thread execution and also synchronize memory with respect to other threads. The following functions synchronize memory with respect to other threads

It then lists a few dozen functions which synchronize memory, including pthread_mutex_lock and pthread_mutex_unlock.

A compiler which wishes to support the pthreads library must implement something to support this cross-thread memory synchronization, even though the C++ specification didn't say anything about it. Fortunately, any compiler where you want to do multithreading was developed with the recognition that such guarantees are fundamental to all multithreading, so every compiler that supports multithreading has it!

In the case of gcc, it did so without any special notes on the pthreads function calls because gcc would effectively create a barrier around every external function call (because it couldn't prove that no synchronization existed inside that function call). If gcc were to ever change that, they would also have to change their pthreads headers to include any extra verbage needed to mark the pthreads functions as synchronizing memory.

All of that, of course, is compiler specific. There were no standards answers to this question until C++11 came along with its new memory model.

NOTE: I am no expert in this area and my knowledge about it is in a spaghetti like condition. So take the answer with a grain of salt.

NOTE-2: This might not be the answer that OP is expecting. But here are my 2 cents anyways if it helps:

My question is that I take a look at GCC5.1 code base and don't see anything special in std::mutex::lock/unlock to prevent compiler reordering codes.

g++ using pthread library. std::mutex is just a thin wrapper around pthread_mutex. So, you will have to actually go and have a look at pthread's mutex implementation.
If you go bit deeper into the pthread implementation (which you can find here), you will see that it uses atomic instructions along with futex calls.

Two minor things to remember here:
1. The atomic instructions do use barriers.
2. Any function call is equivalent to full barrier. Do not remember from where I read it.
3. mutex calls may put the thread to sleep and cause context switch.

Now, as far as reordering goes, one of the things that needs to be guaranteed is that, no instruction after lock and before unlock should be reordered to before lock or after unlock. This I believe is not a full-barrier, but rather just acquire and release barrier respectively. But, this is again platform dependent, x86 provides sequential consistency by default whereas ARM provides a weaker ordering guarantee.

I strongly recommend this blog series:http://preshing.com/archives/It explains lots of lower level stuff in easy to understand language. Guess, I have to read it once again :)

UPDATE:: Unable to comment on @Cort Ammons answer due to length

@Kane I am not sure about this, but people in general write barriers for processor level which takes care of compiler level barriers as well. The same is not true for compiler builtin barriers.

Now, since the pthread_*lock* functions definitions are not present in the translation unit where you are making use of it (this is doubtful), calling lock - unlock should provide you with full memory barrier. The pthread implementation for the platform makes use of atomic instructions to block any other thread from accessing the memory locations after the lock or before unlock. Now since only one thread is executing the critical portion of the code it is ensured that any reordering within that will not change the expected behaviour as mentioned in above comment.

Atomics is pretty tough to understand and to get right, so, what I have written above is from my understanding. Would be very glad to know if my understanding is wrong here.