Numpy, multiply array with scalar [duplicate] Numpy, multiply array with scalar [duplicate] numpy numpy

Numpy, multiply array with scalar [duplicate]


You can multiply numpy arrays by scalars and it just works.

>>> import numpy as np>>> np.array([1, 2, 3]) * 2array([2, 4, 6])>>> np.array([[1, 2, 3], [4, 5, 6]]) * 2array([[ 2,  4,  6],       [ 8, 10, 12]])

This is also a very fast and efficient operation. With your example:

>>> a_1 = np.array([1.0, 2.0, 3.0])>>> a_2 = np.array([[1., 2.], [3., 4.]])>>> b = 2.0>>> a_1 * barray([2., 4., 6.])>>> a_2 * barray([[2., 4.],       [6., 8.]])


Using .multiply() (ufunc multiply)

a_1 = np.array([1.0, 2.0, 3.0])a_2 = np.array([[1., 2.], [3., 4.]])b = 2.0 np.multiply(a_1,b)# array([2., 4., 6.])np.multiply(a_2,b)# array([[2., 4.],[6., 8.]])