Numpy, multiply array with scalar [duplicate]
You can multiply numpy arrays by scalars and it just works.
>>> import numpy as np>>> np.array([1, 2, 3]) * 2array([2, 4, 6])>>> np.array([[1, 2, 3], [4, 5, 6]]) * 2array([[ 2, 4, 6], [ 8, 10, 12]])
This is also a very fast and efficient operation. With your example:
>>> a_1 = np.array([1.0, 2.0, 3.0])>>> a_2 = np.array([[1., 2.], [3., 4.]])>>> b = 2.0>>> a_1 * barray([2., 4., 6.])>>> a_2 * barray([[2., 4.], [6., 8.]])
Using .multiply() (ufunc multiply)
a_1 = np.array([1.0, 2.0, 3.0])a_2 = np.array([[1., 2.], [3., 4.]])b = 2.0 np.multiply(a_1,b)# array([2., 4., 6.])np.multiply(a_2,b)# array([[2., 4.],[6., 8.]])