numpy.ndenumerate to return indices in Fortran order?

You can do it with np.nditer as follows:

it = np.nditer(a, flags=['multi_index'], order='F')while not it.finished:    print it.multi_index, it[0]    it.iternext()

np.nditer is a very powerful beast that exposes some of the internal C iterator in Python, take a look at Iterating Over Arrays in the docs.

python arrays numpy iterator iteration

Just taking a transpose would give you what you want:

a = np.array([[11, 12],              [21, 22],              [31, 32]])for (i,j),v in np.ndenumerate(a.T):    print j, i, v

Result:

0 0 111 0 212 0 310 1 121 1 222 1 32

CodeHunter