oracle date range
Use:
SELECT * FROM x WHERE x.wedding BETWEEN TO_DATE('2008-JUN-01', 'YYYY-MON-DD') AND TO_DATE('2008-JUL-01', 'YYYY-MON-DD')Use of TO_DATE constructs a date with a time portion of 00:00:00, which requires the end date to be one day ahead unless you want to use logic to correct the current date to be one second before midnight. Untested:
TO_DATE('2008-JUN-30', 'YYYY-MON-DD') + 1 - (1/(24*60*60))That should add one day to 30-Jun-2008, and then subtract one second in order to return a final date of 30-Jun-2008 23:59.
References:
This is ANSI SQL, and supported by oracle as of version 9i
SELECT *FROM xWHERE EXTRACT(YEAR FROM wedding) = 2008AND EXTRACT(MONTH FROM wedding) = 06Classic solution with oracle specific TO_CHAR():
SELECT *FROM xWHERE TO_CHAR(wedding, 'YYYY-MMM') = '2008-JUN'(the latter solutions was supported when dinosaurs still walked the earth)