Performance of regexp_replace vs translate in Oracle?
I think you're running into simple optimization. The regexp expression is so expensive to compute that the result is cached in the hope that it will be used again in the future. If you actually use distinct strings to convert, you will see that the modest translate is naturally faster because it is its specialized function.
Here's my example, running on 11.1.0.7.0
:
SQL> DECLARE 2 TYPE t IS TABLE OF VARCHAR2(4000); 3 l t; 4 l_level NUMBER := 1000; 5 l_time TIMESTAMP; 6 l_char VARCHAR2(4000); 7 BEGIN 8 -- init 9 EXECUTE IMMEDIATE 'ALTER SESSION SET PLSQL_OPTIMIZE_LEVEL=2'; 10 SELECT dbms_random.STRING('p', 2000) 11 BULK COLLECT 12 INTO l FROM dual 13 CONNECT BY LEVEL <= l_level; 14 -- regex 15 l_time := systimestamp; 16 FOR i IN 1 .. l.count LOOP 17 l_char := regexp_replace(l(i), '[]()[]', '-', 1, 0); 18 END LOOP; 19 dbms_output.put_line('regex :' || (systimestamp - l_time)); 20 -- tranlate 21 l_time := systimestamp; 22 FOR i IN 1 .. l.count LOOP 23 l_char := translate(l(i), '()[]', '----'); 24 END LOOP; 25 dbms_output.put_line('translate :' || (systimestamp - l_time)); 26 END; 27 /regex :+000000000 00:00:00.979305000translate :+000000000 00:00:00.238773000PL/SQL procedure successfully completed
on 11.2.0.3.0
:
regex :+000000000 00:00:00.617290000translate :+000000000 00:00:00.138205000
Conclusion: In general I suspect translate
will win.
For SQL, I tested this with the following script:
set timing onselect sum(length(x)) from ( select translate('(<FIO>)', '()[]', '----') x from ( select * from dual connect by level <= 2000000 ));select sum(length(x)) from ( select regexp_replace('[(<FIO>)]', '[\(\)\[]|\]', '-', 1, 0) x from ( select * from dual connect by level <= 2000000 ));
and found that the performance of translate
and regexp_replace
were almost always the same, but it could be that the cost of the other operations is overwhelming the cost of the functions I'm trying to test.
Next, I tried a PL/SQL version:
set timing ondeclare x varchar2(100);begin for i in 1..2500000 loop x := translate('(<FIO>)', '()[]', '----'); end loop;end;/declare x varchar2(100);begin for i in 1..2500000 loop x := regexp_replace('[(<FIO>)]', '[\(\)\[]|\]', '-', 1, 0); end loop;end;/
Here the translate
version takes just under 10 seconds, while the regexp_replace
version around 0.2 seconds -- around 2 orders of magnitude faster(!)
Based on this result, I will be using regular expressions much more often in my performance critical code -- both SQL and PL/SQL.