SQL Challenge/Puzzle: Given a stack trace - How to find the top element at each point in time?
This is a nice puzzle.
As my main DBMS is Teradata I wrote a solution for it using Analytical functions (needs TD14.10+):
SELECT dt.*, -- find the last item in the stack with the same position Last_Value(val IGNORE NULLS) Over (PARTITION BY pos ORDER BY i) AS top_of_stack_valFROM ( SELECT st.*, -- calculate the number of items in the stack Sum(CASE WHEN op = 'I' THEN 1 ELSE -1 end) Over (ORDER BY i ROWS Unbounded Preceding) AS pos FROM stack_trace AS st ) AS dt;
This solution works for Oracle, too, but PostgreSQL & SQL Server don't support the IGNORE NULLS
option for LAST_VALUE
and emulating it is quite complicated, e.g see Itzk Ben-Gan's The Last non NULL Puzzle
Edit: In fact it's not that complex, I forgot Itzik's 2nd solution, the old piggyback trick ;-)
Martin Smith's approach will work for all four DBMSes.
Personally I doubt that you will end up finding SQL that you can just use in all of SQL Server, Teradata, Postgres, and Oracle and that has acceptable performance if the table is at all large.
A SQL Server solution (demo) would be as follows
SELECT i, SUBSTRING(MAX(FORMAT(i, 'D10') + val) OVER (PARTITION BY Pos ORDER BY i ROWS UNBOUNDED PRECEDING), 11, 8000)FROM (SELECT st.*, sum(CASE WHEN op = 'I' THEN 1 ELSE -1 END) OVER (ORDER BY i ROWS UNBOUNDED PRECEDING) AS pos FROM stack_trace st) t1ORDER BY i;
Although it does require an additional step -
Generic solution for Hive, Teradata, Oracle, SQL Server and PostgreSQL
select s.i ,min (s.val) over ( partition by s.depth ,s.depth_val_seq ) as top_of_stack_val from (select s.i ,s.val ,s.depth ,count (s.val) over ( partition by s.depth order by s.i rows between unbounded preceding and current row ) as depth_val_seq from (select s.i ,s.val ,sum (case s.op when 'I' then 1 else -1 end) over ( order by s.i rows between unbounded preceding and current row ) as depth from stack_trace s ) s ) s order by i;