Accessing outside variable using anonymous function as params

You have to use use as described in docs:

Closures may also inherit variables from the parent scope. Any such variables must be declared in the function header. Inheriting variables from the parent scope is not the same as using global variables. Global variables exist in the global scope, which is the same no matter what function is executing.

Code:

$result = '';fetch("SELECT title FROM tbl", function($r) use (&$result) {   $result .= $r['title'];});

But beware (taken from one of comments in previous link):

use() parameters are early binding - they use the variable's value at the point where the lambda function is declared, rather than the point where the lambda function is called (late binding).

What about rewriting 'fetch' to call $func only once ?

function fetch($query,$func) {    $query = mysql_query($query);       $retVal = array();    while($r = mysql_fetch_assoc($query)) {        $retVal[] = $r;    }    $func($retVal);}

This way you would call $func only once and re-process the array once fetched?Not sure about the performance even tho calling 200 times a function doesn't sound like a good idea.