Build dynamic array in PHP
Your question is confusing. This is what I understand:
You have the following:
$t
, which is an object.$t->user
, also an object.$t->user[0]->name = 'wilson'
$t->user[0]->first = 'carl'
You say you need to get:
$t->name = 'wilson'
$t->first = 'carl'
You say 'phil' in the question, but the given object $t
has no reference to a 'phil' so I don't know if 'phil' appears out of thin air, or what.
Is this a correct view of the problem? If so, you need to clarify this in the question. saying $t > user > 0 (object) name
makes no sense.
Sorry this is an "answer", I just couldn't fit all of this in a comment. I will delete it if you clarify the question. Hopefully I am not the only person confused by this.
$t = object()$t > user = object()$t > user > 0 (object) name = 'wilson';$t > user > 0 (object) first = 'carl';
This is not valid PHP code. If you want $t
in the format you show, just do this:
$t = array( 'name' => 'wilson', 'first name' => 'phil');
Now $t
is an array, with keys 'name'
and 'first name'
.
Your foreach loop doesn't make any sense. $t
is an array of two strings. Looping over it will just give the values 'wilson'
and 'phil'
.
EDIT: Assuming $t
was given to you, then your for loop should look like this:
foreach($t as $a) { foreach($a as $l) { $arr[$l->{0}->name] = $l->{0}->first; } }
You can't do $l->0
. You need to wrap the 0
in {}
. $l->{0}
.