How to find the dates between two specified date?

I am pretty sure this has been answered a quadrillion times before, but anyway:

$start = strtotime('20-04-2010 10:00');$end   = strtotime('22-04-2010 10:00');for($current = $start; $current <= $end; $current += 86400) {    echo date('d-m-Y', $current);}

The 10:00 part is to prevent the code to skip or repeat a day due to daylight saving time.

By giving the number of days:

for($i = 0; $i <= 2; $i++) {    echo date('d-m-Y', strtotime("20-04-2010 +$i days"));}

With PHP5.3

$period = new DatePeriod(    new DateTime('20-04-2010'),    DateInterval::createFromDateString('+1 day'),    new DateTime('23-04-2010') // or pass in just the no of days: 2);foreach ( $period as $dt ) {  echo $dt->format( 'd-m-Y' );}

You can use mktime().

mktime() is useful for doing date arithmetic and validation, as it will automatically calculate the correct value for out-of-range input.

If you increment the day number you get a valid date back, even if you go past the end of the month:

<?php$day= 25;$dateEnd = mktime(0,0,0,5,3,2010);do {    $dateCur = mktime(0,0,0,4,$day,2010);    $day++;    print date( 'd-m-y', $dateCur) .'<br>';} while ($dateCur < $dateEnd);

Output:

25-04-1026-04-1027-04-1028-04-1029-04-1030-04-1001-05-1002-05-1003-05-10

You can do:

$start = strtotime("2010-04-20"); // get timestamp for start date.$end = strtotime("2010-04-22");   // get timestamp for end date.// go from start timestamp to end timestamp adding # of sec in a day.for($t=$start;$t<=$end;$t+=86400) {        // get the date for this timestamp.        $d = getdate($t);        // print the date.        echo $d['mday'].'-'.$d['mon'].'-'.$d['year']."\n";}

Output:

20-4-201021-4-201022-4-2010