How to get redirector.googlevideo.com link from a Google drive video
Php code will not work here and even meaningless, because it will return the result for server side.
This is my Javascript/Ajax code.Unfortunately, you should use Access-Control-Allow-Origin extension in Chrome browser.First, please see this screenshot of console window.
<!DOCTYPE html><html> <head> <script src="https://code.jquery.com/jquery-3.2.1.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script> <script src="https://content.jwplatform.com/libraries/YOUR-JW-PLAYER-LICENSE-KEY.js"></script> </head> <body> <p id="urls"></p> <div id="myElement"></div> </body> <script> var docid = "0B4Mn0g4wWmQ1ZThycVhOcDJQc2c"; var api_url = "https://docs.google.com/get_video_info"; var ans = {}; var url = ""; getGoogleVideoUrl(); function getGoogleVideoUrl(){ $.ajax({ url: api_url, type: "get", data: { docid: docid, }, success: function(response) { // // get value of which key is 'fmt_stream_map'. // var fmt_stream_map = getQueryVariable(response, 'fmt_stream_map'); // // split my comma // var maps = fmt_stream_map.split("%2C"); // // loop all links, // var purl = ""; for (x in maps) { var res = decodeURIComponent(decodeURIComponent(maps[x])).split('|'); // purl = res[1].replace(new RegExp("/\/[^\/]+\.google\.com/", 'g'),"//redirector.googlevideo.com/"); // purl = res[1].replace(new RegExp("\.google\.com/", 'g'),".googlevideo.com/"); purl = res[1]; //.replace(/.c.docs.google.com/g,".googlevideo.com") //.replace(/app=explorer/g,"app=storage") //.replace(/key=ck2/g,"key=cms1") //.replace(/&cp=/g,"&api=") //.replace(/,cp&/g,',api&') //.replace(/,cp,/g,',api,') //.replace(/=cp,/g,'=api,') //.replace(/&sparams=/g,'&cms_redirect=yes&sparams='); switch (parseInt(res[0])) { case 5: quality = 'Low Quality, 240p, FLV, 400x240'; break; case 17: quality = 'Low Quality, 144p, 3GP, 0x0'; break; case 18: quality = 'Medium Quality, 360p, MP4, 480x360'; break; case 22: quality = 'High Quality, 720p, MP4, 1280x720'; break; case 34: quality = 'Medium Quality, 360p, FLV, 640x360'; break; case 35: quality = 'Standard Definition, 480p, FLV, 854x480'; break; case 36: quality = 'Low Quality, 240p, 3GP, 0x0'; break; case 37: quality = 'Full High Quality, 1080p, MP4, 1920x1080'; break; case 38: quality = 'Original Definition, MP4, 4096x3072'; break; case 43: quality = 'Medium Quality, 360p, WebM, 640x360'; break; case 44: quality = 'Standard Definition, 480p, WebM, 854x480'; break; case 45: quality = 'High Quality, 720p, WebM, 1280x720'; break; case 46: quality = 'Full High Quality, 1080p, WebM, 1280x720'; break; case 82: quality = 'Medium Quality 3D, 360p, MP4, 640x360'; break; case 84: quality = 'High Quality 3D, 720p, MP4, 1280x720'; break; case 102: quality = 'Medium Quality 3D, 360p, WebM, 640x360'; break; case 104: quality = 'High Quality 3D, 720p, WebM, 1280x720'; break; default: quality = 'transcoded (unknown) quality'; break; } ans[quality] = purl; } console.log(ans); $('#urls').html(JSON.stringify(ans)); url = ans[Object.keys(ans)[0]]; build_player(); }, error: function(xhr) { //Do Something to handle error } }); } function build_player(){ var playerInstance = jwplayer("myElement"); playerInstance.setup({ file: url, type: "mp4", width: 800 , height: 600, }); } function getQueryVariable(query, variable) { var vars = query.split('&'); for (var i = 0; i < vars.length; i++) { var pair = vars[i].split('='); if (decodeURIComponent(pair[0]) == variable) { //return decodeURIComponent(pair[1]); return pair[1]; } } console.log('Query variable %s not found', variable); return ""; } </script></html>This code works basically, but doesn't play in jwplayer component.
However, if you enter this URL, "https://docs.google.com/get_video_info?docid=0B4Mn0g4wWmQ1ZThycVhOcDJQc2c", directly in chrome browser, get JSON file , parse it manually, use one of URLs directly in this code as jwplayer's file url, it works perfectly, although it contains "app=explorer" tag in itself.
I'm not sure why this happens.So I tried to compare 2 links and some parameters is different. The first one is from above code and not working, the 2nd JSON file directly and working.)
ei=hJ5yWaHCKYXb-wWona2YBAei=KZ5yWZSkK4aFqgXAwpoosusci=o-AC34EOoA1Wst0Heh0U_bP9epqR8K9s4UBhwlqmsxKZKwAOAsusci=o-AH82qbGL8BcWQ3BPybbvZyuNBiDd2Uasz4J0ZNXJCZwobPjeexpire=1500698308expire=1500698217cp=QVNFUkdfV1NOSVhOOnhwOWFybUloWXNXcp=QVNFUkdfV1JPSFhOOmpURGRUeUt3eVpvsignature=3D306FD9D9ADA683D313AABDFE057B608A6F2A39.8BB3A9C321B6BEAC8D1D5AEED2F25511DF97CE2Bsignature=2C2465BDFC4D9CCFD0D4A42F38BAEF44D55AFDF1.A916937113445ABB90D18B3AE89600729CFADDE6Why first one is not working while 2nd is working?Any idea of this?
He is talking about getting the URL from google drive all qualities in 360p,480p,720p,1080p and convert just before the /videoplayback to redirector.googlevideo.com and make it as video/mp4 to do playback in JW Player.I have the full script but it has got a minor problem it says forbidden 403 and it is because of changes google made in API.Have a look at the codes in PHP and let me know if someone can fix it,i will post full script later.
function Drive($link) { $url = urldecode($link); $get = curl1($url); $data = explode(',["fmt_stream_map","', $get); $data = explode('"]', $data[1]); $data = str_replace(array('\u003d', '\u0026'), array('=', '&'), $data[0]); $data = explode(',', $data); asort($data); foreach($data as $list) { $data2 = explode('|', $list); if($data2[0] == 37) {$q1080p = preg_replace("/\/[^\/]+\.google\.com/","/redirector.googlevideo.com",$data2[1]);} // 1080P if($data2[0] == 22) {$q720p = preg_replace("/\/[^\/]+\.google\.com/","/redirector.googlevideo.com",$data2[1]);} // 720P if($data2[0] == 59) {$q480p = preg_replace("/\/[^\/]+\.google\.com/","/redirector.googlevideo.com",$data2[1]);} // 480P if($data2[0] == 18) {$q360p = preg_replace("/\/[^\/]+\.google\.com/","/redirector.googlevideo.com",$data2[1]);} // 360P } $js[0][0] = "$q1080p"; $js[0][1] = "$q720p"; $js[0][2] = "$q480p"; $js[0][3] = "$q360p"; $js[1][0] = "1080P"; $js[1][1] = "720P"; $js[1][2] = "480P"; $js[1][3] = "360P"; return $js; }if ($jw[0][0] != "") { echo('{file: "'.urldecode($jw[0][0]).'",type: "video/mp4",label: "'.urldecode($jw[1][0]).'"},');}if ($jw[0][1] != "") { echo('{file: "'.urldecode($jw[0][1]).'",type: "video/mp4",label: "'.urldecode($jw[1][1]).'"},');} if ($jw[0][2] != "") { echo('{file: "'.urldecode($jw[0][2]).'",type: "video/mp4",label: "'.urldecode($jw[1][2]).'"},');} if ($jw[0][3] != "") { echo('{file: "'.urldecode($jw[0][3]).'",type: "video/mp4",label: "'.urldecode($jw[1][3]).'"},');}
I implemented a better algorithm from the previous answer.
function curl($url){ $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch,CURLOPT_RETURNTRANSFER, $return); $result = curl_exec($ch); curl_close($ch); return $result;}function Drive($id) { $o = []; $url = "https://docs.google.com/get_video_info?docid=$id"; $get = curl($url); parse_str($get, $out); $data = explode(",", $out["fmt_stream_map"]); foreach($data as $d) { switch ((int)substr($d, 0, 2)) { case 18: $r = "360P"; break; case 22: $r = "720P"; break; case 37: $r = "1080P"; break; case 59: $r = "480P"; break; default: break; } $o[$r] = substr(preg_replace("/\/[^\/]+\.google\.com/","/redirector.googlevideo.com", $d), 3); } ksort($o); return $o;}$jw = Drive(FILE_ID_HERE);foreach ($jw as $k => $r) { echo json_encode(array("file"=> $r, "type"=> "video/mp4", "label"=> $k))."\n";}