How to work with infinity arguments in a function (like PHP's isset()) [duplicate]

func_get_args will do what you want:

function infinite_parameters() {    foreach (func_get_args() as $param) {        echo "Param is $param" . PHP_EOL;    }}

You can also use func_get_arg to get a specific parameter (it's zero-indexed):

function infinite_parameters() {    echo func_get_arg(2);}

But be careful to check that you have that parameter:

function infinite_parameters() {    if (func_num_args() < 3) {        throw new BadFunctionCallException("Not enough parameters!");    }}

You can even mix together func_*_arg and regular parameters:

function foo($param1, $param2) {    echo $param1; // Works as normal    echo func_get_arg(0); // Gets $param1    if (func_num_args() >= 3) {        echo func_get_arg(2);    }}

But before using it, think about whether you really want to have indefinite parameters. Would an array not suffice?

Starting with PHP 5.6 you can use the token "..."

Example:

<?phpfunction sum(...$numbers) {    $acc = 0;    foreach ($numbers as $n) {        $acc += $n;    }    return $acc;}echo sum(1, 2, 3, 4);?>

Source:http://php.net/manual/en/functions.arguments.php#functions.variable-arg-list

You can use func_get_args(), it will return an array of arguments.

function work_with_arguments() {    echo implode(", ", func_get_args());}work_with_arguments("Hello", "World");//Outputs: Hello, World