Passing $_GET parameters to cron job
The $_GET[]
& $_POST[]
associative arrays are only initialized when your script is invoked via a web server. When invoked via the command line, parameters are passed in the $argv
array, just like C.
Contains an array of all the arguments passed to the script when running from the command line.
Your command would be:
* 3 * * * /path_to_script/cronjob.php username=test password=test code=1234
You would then use parse_str() to set and access the paramaters:
<?phpvar_dump($argv);/*array(4) { [0]=> string(27) "/path_to_script/cronjob.php" [1]=> string(13) "username=test" [2]=> string(13) "password=test" [3]=> string(9) "code=1234"}*/parse_str($argv[3], $params);echo $params['code']; // 1234
Not a direct answer to your question but a better solution I think:
If you want nobody except cron to run the script, just place it outside the web-root. That way there is no access via the web-server at all.
If you do need to run the command as a special user as well, don't use GET
but have a user login and check for a logged-in session (a certain set session variable...) and include the script in that page only.
Your publicly accessible script would look something like:
session_start();if (isset($_SESSION['user'])){ include '/path/to/script/outside/of/web-root';}else{ die('No access.');}
* 3 * * * /path_to_script/cronjob.php?username=test&password=test&code=1234
This will not work
* 3 * * * /path_to_script/cronjob.php username=test password=test code=1234
This works
Also, you need to use parse_str() function and get value
$str = "first=value&arr[]=foo+bar&arr[]=baz";parse_str($str);echo $first; // valueecho $arr[0]; // foo barecho $arr[1]; // baz