php: Declare arguments type of a Function

Type Hints can only be of the object and array (since PHP 5.1) type. Traditional type hinting with int and string isn't supported.

Since string and int are not classes, you can't "type-hint" them in your function.

As of PHP 7.0 declaring argument type as string, int, float, bool is supported.

php function arguments

This maybe useful for anyone who see this post since the availability of PHP 7

With PHP 7, its now possible to declare types. You can refer the following link for more information.

function(string $name, boolean $is_admin) {    //do something}

php function arguments

You can do something like this which has always worked for me

for string

function setData($Name=""){ }

this forces the name to be a string, it doesn't check if its a string

for numeric values

function setData($age=0){ }

this forces the age to be a number, if a string is passed, the value will be 0

for array values , there are two variation

function setData(array $data){ }

if an array is not passed, it would throw an error

function setData($data=array()){ }

This would pass an empty array of no value is given for $data

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