PHP: How to pass instance variable to closure?
You can use your workaround. You can also be more general:
$self = $this;$func = function() use ($self) { echo "myVar = " . $self->myVar;};Within the closure you can access any public properties or methods using $self instead of $this.
But it won't work for the original question, because the variable in question is private.
Why not ?:
$func = function($param){ echo 'myVar is: ' . $param; }; $func($this->myVar);Update:
@Bramar right. But, if only $myVar will be public, it will work. Closures have no associated scope , so they cannot access private and protected members. In you specific case, you can do:
$this->myVar = 5; $_var = $this->myVar; $func = function() use ($_var) { echo 'myVar is: ' . $_var; }; $func();