PHP pass default argument to function
This is not natively possible in PHP. There are workarounds like using arrays to pass all parameters instead of a row of arguments, but they have massive downsides.
The best manual workaround that I can think of is defining a constant with an arbitrary value that can't collide with a real value. For example, for a parameter that can never be -1:
define("DEFAULT_ARGUMENT", -1);and test for that:
function($foo = DEFAULT_ARGUMENT, $bar = false){}
The usual approach to this is that if (is_null($foo)) the function replaces it with the default. Use null, empty string, etc. to "skip" arguments. This is how most built-in PHP functions that need to skip arguments do it.
<?phpfunction($foo = null, $bar = false) { if (is_null($foo)) { $foo = 12345; } }?>