BrowseForFolder-Dialog: center and make TopMost

You have to specify the owner handle.

$handle = [System.Diagnostics.Process]::GetCurrentProcess().MainWindowHandle$getfolder = New-Object -ComObject Shell.Application$foldername = $getfolder.BrowseForFolder([int]$handle, "Text", 16, "")

But it is a mixture of COM and .NET. I recommend the following solution

$win32WindowDefinition = @"using System;using System.Windows.Forms;public class Win32Window : IWin32Window{    public Win32Window(IntPtr handle)    {        Handle = handle;    }    public IntPtr Handle { get; private set; }}"@Add-Type -TypeDefinition $win32WindowDefinition -ReferencedAssemblies System.Windows.Forms.dll $ownerHandle = New-Object Win32Window -ArgumentList ([System.Diagnostics.Process]::GetCurrentProcess().MainWindowHandle)$folderBrowserDialog = New-Object System.Windows.Forms.FolderBrowserDialog$dialogResult = $folderBrowserDialog.ShowDialog($ownerHandle)if ($dialogResult -eq [System.Windows.Forms.DialogResult]::OK) {    $folderName = $folderBrowserDialog.SelectedPath}

from http://poshcode.org/2002

If you can use FolderBrowserDialog, to show it as top-most and at the center of screen, it's enough to pass a TopMost form to its ShowDialog method.

C# Example

var f = new FolderBrowserDialog();f.ShowDialog(new Form() { TopMost = true}); this.Activate();

Powershell Example

[System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms")$folder = New-Object System.Windows.Forms.FolderBrowserDialog$form = New-Object System.Windows.Forms.Form -property @{TopMost = $True}$folder.ShowDialog($form)