PowerShell Math Problem?
To call other3 with two parameters, drop the parenthesis "()" e.g.
$a = other3 $x $yThe way you're currently calling it, actually passes one parameter, an array with two elements, i.e. 5 and 10. The second parameter is empty (probably defaults to null), meaning the addition does nothing and you simply return the $x parameter.
You're passing a list (5,10) to the parameter $x and $null to $y.
When the function adds $null to the list, you just get the list back.
Adding some write-host statements to the function should make this clear:
function other3($x, $y){ $tmp = $x + $y write-host "`x=($x)" write-host "`y=($y)" return $tmp}$x = 5$y = 10$a = other3($x, $y)Write-Host $a