Powershell Start Process, Wait with Timeout, Kill and Get Exit Code
You can terminate the process more simply using $proc | kill or $proc.Kill(). Be aware, that you won't be able to retrieve a exit code in this case, you should rather just update the internal error counter:
for ($i=0; $i -le $max_iterations; $i++){ $proc = Start-Process -filePath $programtorun -ArgumentList $argumentlist -workingdirectory $programtorunpath -PassThru # keep track of timeout event $timeouted = $null # reset any previously set timeout # wait up to x seconds for normal termination $proc | Wait-Process -Timeout 4 -ErrorAction SilentlyContinue -ErrorVariable timeouted if ($timeouted) { # terminate the process $proc | kill # update internal error counter } elseif ($proc.ExitCode -ne 0) { # update internal error counter }}