Accessing dict_keys element by index in Python3
Call list() on the dictionary instead:
keys = list(test)In Python 3, the dict.keys() method returns a dictionary view object, which acts as a set. Iterating over the dictionary directly also yields keys, so turning a dictionary into a list results in a list of all the keys:
>>> test = {'foo': 'bar', 'hello': 'world'}>>> list(test)['foo', 'hello']>>> list(test)[0]'foo'
Not a full answer but perhaps a useful hint. If it is really the first item you want*, then
next(iter(q))is much faster than
list(q)[0]for large dicts, since the whole thing doesn't have to be stored in memory.
For 10.000.000 items I found it to be almost 40.000 times faster.
*The first item in case of a dict being just a pseudo-random item before Python 3.6 (after that it's ordered in the standard implementation, although it's not advised to rely on it).
I wanted "key" & "value" pair of a first dictionary item. I used the following code.
key, val = next(iter(my_dict.items()))