Calling a class method raises a TypeError in Python

You can instantiate the class by declaring a variable and calling the class as if it were a function:

x = mystuff()print x.average(9,18,27)

However, this won't work with the code you gave us. When you call a class method on a given object (x), it always passes a pointer to the object as the first parameter when it calls the function. So if you run your code right now, you'll see this error message:

TypeError: average() takes exactly 3 arguments (4 given)

To fix this, you'll need to modify the definition of the average method to take four parameters. The first parameter is an object reference, and the remaining 3 parameters would be for the 3 numbers.

From your example, it seems to me you want to use a static method.

class mystuff:  @staticmethod  def average(a,b,c): #get the average of three numbers    result=a+b+c    result=result/3    return resultprint mystuff.average(9,18,27)

Please note that an heavy usage of static methods in python is usually a symptom of some bad smell - if you really need functions, then declare them directly on module level.

To minimally modify your example, you could amend the code to:

class myclass(object):        def __init__(self): # this method creates the class object.                pass        def average(self,a,b,c): #get the average of three numbers                result=a+b+c                result=result/3                return resultmystuff=myclass()  # by default the __init__ method is then called.      print mystuff.average(a,b,c)

Or to expand it more fully, allowing you to add other methods.

class myclass(object):        def __init__(self,a,b,c):                self.a=a                self.b=b                self.c=c        def average(self): #get the average of three numbers                result=self.a+self.b+self.c                result=result/3                return resulta=9b=18c=27mystuff=myclass(a, b, c)        print mystuff.average()