Get a random sample with replacement

In Python 3.6, the new random.choices() function will address the problem directly:

>>> from random import choices>>> colors = ["R", "G", "B", "Y"]>>> choices(colors, k=4)['G', 'R', 'G', 'Y']

python python-3.x random

print([random.choice(colors) for _ in colors])

If the number of values you need does not correspond to the number of values in the list, then use range:

print([random.choice(colors) for _ in range(7)])

From Python 3.6 onwards you can also use random.choices (plural) and specify the number of values you need as the k argument.

python python-3.x random

Try numpy.random.choice (documentation numpy-v1.13):

import numpy as npn = 10 #size of the sample you wantprint(np.random.choice(colors,n))

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