Matching Unicode word boundaries in Python
1- RIGHT SINGLE QUOTATION MARK ’ seems to be just simply missed in source file:
/* Break between apostrophe and vowels (French, Italian). *//* WB5a */if (pos_m1 >= 0 && char_at(state->text, pos_m1) == '\'' && is_unicode_vowel(char_at(state->text, text_pos))) return TRUE;2- Unicode vowels are determined with is_unicode_vowel() function which translates to this list:
a, à, á, â, e, è, é, ê, i, ì, í, î, o, ò, ó, ô, u, ù, ú, ûSo a LATIN SMALL LIGATURE OE œ character is not considered as a unicode vowel:
Py_LOCAL_INLINE(BOOL) is_unicode_vowel(Py_UCS4 ch) {#if PY_VERSION_HEX >= 0x03030000 switch (Py_UNICODE_TOLOWER(ch)) {#else switch (Py_UNICODE_TOLOWER((Py_UNICODE)ch)) {#endif case 'a': case 0xE0: case 0xE1: case 0xE2: case 'e': case 0xE8: case 0xE9: case 0xEA: case 'i': case 0xEC: case 0xED: case 0xEE: case 'o': case 0xF2: case 0xF3: case 0xF4: case 'u': case 0xF9: case 0xFA: case 0xFB: return TRUE; default: return FALSE; }}This bug is now fixed in regex 2016.08.27 after a bug report. [_regex.c:#1668]