Regular expression to return text between parenthesis
If your problem is really just this simple, you don't need regex:
s[s.find("(")+1:s.find(")")]
Use re.search(r'\((.*?)\)',s).group(1):
>>> import re>>> s = u'abcde(date=\'2/xc2/xb2\',time=\'/case/test.png\')'>>> re.search(r'\((.*?)\)',s).group(1)u"date='2/xc2/xb2',time='/case/test.png'"
If you want to find all occurences:
>>> re.findall('\(.*?\)',s)[u"(date='2/xc2/xb2',time='/case/test.png')", u'(eee)']>>> re.findall('\((.*?)\)',s)[u"date='2/xc2/xb2',time='/case/test.png'", u'eee']