Sort string list by a number in string?
the key is ... the key
sorted(names, key=lambda x: int(x.partition('-')[2].partition('.')[0]))Getting that part of the string recognized as the sort order by separating it out and transforming it to an int.
Some alternatives:
(1) Slicing by position:
sorted(names, key=lambda x: int(x[5:-6]))(2) Stripping substrings:
sorted(names, key=lambda x: int(x.replace('Test-', '').replace('.model', '')))(3) Splitting characters (also possible via str.partition):
sorted(names, key=lambda x: int(x.split('-')[1].split('.')[0]))(4) Map with np.argsort on any of (1)-(3):
list(map(names.__getitem__, np.argsort([int(x[5:-6]) for x in names])))
I found a similar question and a solution by myself.Nonalphanumeric list order from os.listdir() in Python
import redef sorted_alphanumeric(data): convert = lambda text: int(text) if text.isdigit() else text.lower() alphanum_key = lambda key: [ convert(c) for c in re.split('([0-9]+)', key) ] return sorted(data, key=alphanum_key, reverse=True)