Turn slice into range

There's an easier way to do this (at least in 3.4, I don't have 3.3 at the moment, and I don't see it in the changelog).

Assuming your class already has a known length you can just slice a range of that size:

>>> range(10)[1:5:2]range(1, 5, 2)>>> list(range(10)[1:5:2])[1, 3]

If you don't know the length a priori you'll have to do:

>>> class A:    def __getitem__(self, item):        if isinstance(item, slice):            return list(range(item.stop)[item])>>> a = A()>>> a[1:5:2][1, 3]>>> a[1:5][1, 2, 3, 4]

Try

class A:    def __getitem__(self, item):        ifnone = lambda a, b: b if a is None else a        if isinstance(item, slice):            if item.stop is None:                # do something with itertools.count()            else:                return list(range(ifnone(item.start, 0), item.stop, ifnone(item.step, 1)))        else:            return item

This will reinterpret .start and .step appropriately if they are None.

Another option could be the .indices() method of a slice. It is called with the number of entries and reinterprets None to the appropriate values and wraps negative values around the given length parameter:

>>> a=slice(None, None, None)>>> a.indices(1)(0, 1, 1)>>> a.indices(10)(0, 10, 1)>>> a=slice(None, -5, None)>>> a.indices(100)(0, 95, 1)

It depends what you intend to do with negative indices...

The problem:

A slice consists of start, stop, and step parameters and can be created with either slice notation or using the slice built-in. Any (or all) of the start, stop, and step parameters can be None.

# validsliceable[None:None:None]# also validcut = slice(None, None, None)sliceable[cut]

However, as pointed out in the original question, the range function does not accept None arguments. You can get around this in various ways...

The solutions

With conditional logic:

if item.start None:    return list(range(item.start, item.stop))return list(range(item.start, item.stop, item.step))

...which can get unnecessarily complex since any or all of the parameters may be None.

With conditional variables:

start = item.start if item.start is None else 0step = item.step if item.step is None else 1return list(range(item.start, item.stop, item.step))

... which is explicit, but a little verbose.

With conditionals directly in the statement:

return list(range(item.start if item.start else 0, item.stop, item.step if item.step else 1))

... which is also unnecessarily verbose.

With a function or lambda statement:

ifnone = lambda a, b: b if a is None else arange(ifnone(item.start, 0), item.stop, ifnone(item.step, 1)

...which can be difficult to understand.

With 'or':

return list(range(item.start or 0, item.stop or len(self), item.step or 1))

I find using or to assign sensible default values the simplest. It's explicit, simple, clear, and concise.

Rounding out the implementation

To complete the implementation you should also handle integer indexes (int, long, etc) by checking isinstance(item, numbers.Integral) (see int vs numbers.Integral).

Define __len__ to allow for using len(self) for a default stop value.

Finally raise an appropriate TypeError for invalid indexes (e.g. strings, etc).

TL;DR;

class A:    def __len__(self):        return 0    def __getitem__(self, item):        if isinstance(item, numbers.Integral):  # item is an integer            return item        if isinstance(item, slice):  # item is a slice            return list(range(item.start or 0, item.stop or len(self), item.step or 1))        else:  # invalid index type            raise TypeError('{cls} indices must be integers or slices, not {idx}'.format(                cls=type(self).__name__,                idx=type(item).__name__,            ))