Where is the NoneType located in Python 3.x?
You can use type(None)
to get the type object, but you want to use isinstance()
here, not type() in {...}
:
assert isinstance(value, (str, type(None)))
The NoneType
object is not otherwise exposed anywhere.
I'd not use type checking for that at all really, I'd use:
assert value is None or isinstance(value, str)
as None
is a singleton (very much on purpose) and NoneType
explicitly forbids subclassing anyway:
>>> type(None)() is NoneTrue>>> class NoneSubclass(type(None)):... pass... Traceback (most recent call last): File "<stdin>", line 1, in <module>TypeError: type 'NoneType' is not an acceptable base type
types.NoneType
is being reintroduced in Python 3.10.
Improved Modules
Reintroduced the
types.EllipsisType
,types.NoneType
andtypes.NotImplementedType
classes, providing a new set of types readily interpretable by type checkers. (Contributed by Bas van Beek in bpo-41810.)
The discussion about the change was motivated by a need for types.EllipsisType
, leading to types.NoneType
also being added for consistency.
Please use type(None)
. You can use python shell to check like in the below function in which I use type(None)
in order to change from None
to NoneType
.
def to_unicode(value):'''change value to unicode'''try: if isinstance(value, (str,type(None))): return value if not isinstance(value, bytes): raise TypeError("Expected bytes, unicode, or None; got %r" % type(value)) return value.decode("utf-8")except UnicodeDecodeError: return repr(value)