BeautifulSoup HTML table parsing
start = cols[1].find('a').stringor simpler
start = cols[1].a.stringor better
start = str(cols[1].find(text=True))and
entry = [str(x) for x in cols.findAll(text=True)]
I was trying to reproduce your error, but the source html page was changed.
About the error, I had a similar problem, trying to reproduce the example is here
changing the proposed URL for a Wikipedia Table
I fixed it moving to BeautifulSoup4
from bs4 import BeautifulSoupand changing the .string for .get_text()
start = cols[1].get_text()I couldn't test with your example (as I said before, I couldn't reproduce the error) but I think it could be useful for people are looking for a solution to this problem.