Call to operating system to open url?

Here is how to open the user's default browser with a given url:

import webbrowserwebbrowser.open(url[, new=0[, autoraise=True]])

Here is the documentation about this functionality. It's part of Python's stdlibs:

http://docs.python.org/library/webbrowser.html

I have tested this successfully on Linux, Ubuntu 10.10.

Personally I really wouldn't use the webbrowser module.

It's a complicated mess of sniffing for particular browsers, which will won't find the user's default browser if they have more than one installed, and won't find a browser if it doesn't know the name of it (eg Chrome).

Better on Windows is simply to use the os.startfile function, which also works on a URL. On OS X, you can use the open system command. On Linux there's xdg-open, a freedesktop.org standard command supported by GNOME, KDE and XFCE.

if sys.platform=='win32':    os.startfile(url)elif sys.platform=='darwin':    subprocess.Popen(['open', url])else:    try:        subprocess.Popen(['xdg-open', url])    except OSError:        print 'Please open a browser on: '+url

This will give a better user experience on mainstream platforms. You could fall back to webbrowser on other platforms, perhaps. Though most likely if you're on an obscure/unusual/embedded OS where none of the above work, chances are webbrowser will fail too.

Then how about mixing codes of @kobrien and @bobince up:

import subprocessimport webbrowserimport sysurl = 'http://test.com'if sys.platform == 'darwin':    # in case of OS X    subprocess.Popen(['open', url])else:    webbrowser.open_new_tab(url)