Can a dictionary be passed to django models on create?

If title and body are fields in your model, then you can deliver the keyword arguments in your dictionary using the ** operator.

Assuming your model is called MyModel:

# create instance of modelm = MyModel(**data_dict)# don't forget to save to database!m.save()

As for your second question, the dictionary has to be the final argument. Again, extra and extra2 should be fields in the model.

m2 =MyModel(extra='hello', extra2='world', **data_dict)m2.save()

Not directly an answer to the question, but I find this code helped me create the dicts that save nicely into the correct answer. The type conversions made are required if this data will be exported to json.

I hope this helps:

  #mod is a django database model instancedef toDict( mod ):  import datetime  from decimal import Decimal  import re    #Go through the object, load in the objects we want  obj = {}  for key in mod.__dict__:    if re.search('^_', key):      continue      #Copy my data    if isinstance( mod.__dict__[key], datetime.datetime ):      obj[key] = int(calendar.timegm( ts.utctimetuple(mod.__dict__[key])))    elif isinstance( mod.__dict__[key], Decimal ):      obj[key] = float( mod.__dict__[key] )    else:      obj[key] = mod.__dict__[key]  return obj def toCsv( mod, fields, delim=',' ):  import datetime  from decimal import Decimal    #Dump the items  raw = []  for key in fields:    if key not in mod.__dict__:      continue      #Copy my data    if isinstance( mod.__dict__[key], datetime.datetime ):      raw.append( str(calendar.timegm( ts.utctimetuple(mod.__dict__[key]))) )    elif isinstance( mod.__dict__[key], Decimal ):      raw.append( str(float( mod.__dict__[key] )))    else:      raw.append( str(mod.__dict__[key]) )  return delim.join( raw )

For any model DummyModel you can use DummyModel.objects.create(**data_dict). Does not require save after the create.