Can I get an item from a PriorityQueue without removing it yet?
If a is a PriorityQueue object, You can use a.queue[0] to get the next item:
from queue import PriorityQueuea = PriorityQueue()a.put((10, "a"))a.put((4, "b"))a.put((3,"c"))print(a.queue[0])print(a.queue)print(a.get())print(a.queue)print(a.get())print(a.queue)output is :
(3, 'c')[(3, 'c'), (10, 'a'), (4, 'b')](3, 'c')[(4, 'b'), (10, 'a')](4, 'b')[(10, 'a')]but be careful about multi thread access.
If you want next element in the PriorityQueue, in the order of the insertion of the elements, use:
for i in range(len(queue.queue)): print queue.queue[i]this will not pop anything out.
If you want it in the priority order, use:
for i in range(len(queue.queue)): temp = queue.get() queue.put(temp) print tempIf you are using a tuple, instead of a single variable, replace temp by:
((temp1,temp2))
Assuming your items stored in the PriorityQueue is a tuple (priority, value),
def peek(pq): return pq.queue[0][1]