Check if all values in list are greater than a certain number

Use the all() function with a generator expression:

>>> my_list1 = [30, 34, 56]>>> my_list2 = [29, 500, 43]>>> all(i >= 30 for i in my_list1)True>>> all(i >= 30 for i in my_list2)False

Note that this tests for greater than or equal to 30, otherwise my_list1 would not pass the test either.

If you wanted to do this in a function, you'd use:

def all_30_or_up(ls):    for i in ls:        if i < 30:            return False    return True

e.g. as soon as you find a value that proves that there is a value below 30, you return False, and return True if you found no evidence to the contrary.

Similarly, you can use the any() function to test if at least 1 value matches the condition.

...any reason why you can't use min()?

def above(my_list, minimum):    if min(my_list) >= minimum:        print "All values are equal or above", minimum    else:        print "Not all values are equal or above", minimum

I don't know if this is exactly what you want, but technically, this is what you asked for...

There is a builtin function all:

all (x > limit for x in my_list)

Being limit the value greater than which all numbers must be.