Choosing a file in Python with simple Dialog
How about using tkinter?
from Tkinter import Tk # from tkinter import Tk for Python 3.xfrom tkinter.filedialog import askopenfilenameTk().withdraw() # we don't want a full GUI, so keep the root window from appearingfilename = askopenfilename() # show an "Open" dialog box and return the path to the selected fileprint(filename)Done!
Python 3.x version of Etaoin's answer for completeness:
from tkinter.filedialog import askopenfilenamefilename = askopenfilename()
With EasyGui:
import easyguiprint(easygui.fileopenbox())To install:
pip install easyguiDemo:
import easyguieasygui.egdemo()