Contains of HashSet<Integer> in Python
Just use a set:
>>> l = set()>>> l.add(1)>>> l.add(2)>>> 1 in lTrue>>> 34 in lFalseThe same works for lists:
>>> ll = [1,2,3]>>> 2 in llTrue>>> 23 in llFalseEdit:Note @bholagabbar's comment below that the time complexity for in checks in lists and tuples is O(n) on average (see the python docs here), whereas for sets it is on average O(1) (worst case also O(n), but is very uncommon and might only happen if __hash__ is implemented poorly).
In Python, there is a built-in type, set.The major difference from the hashmap in Java is that the Python set is not typed,i.e., it is legal to have a set {'2', 2} in Python.
Out of the box, the class set does not have a contains() method implemented.We typically use the Python keyword in to do what you want, i.e.,
A = [1, 2, 3]S = set()S.add(2)for x in A: if x in S: print("Example")If that does not work for you, you can invoke the special method __contains__(), which is NOT encouraged.
A = [1, 2, 3]S = set()S.add(2)for x in A: if S.__contains__(x): print("Example")