Converting datetime.date to UTC timestamp in Python
d = date(2011, 1, 1) is in UTC:
from datetime import datetime, dateimport calendar timestamp1 = calendar.timegm(d.timetuple()) datetime.utcfromtimestamp(timestamp1)datetime.datetime(2011, 1, 1, 0, 0)
d is in local timezone:
import time timestamp2 = time.mktime(d.timetuple()) # DO NOT USE IT WITH UTC DATEdatetime.fromtimestamp(timestamp2)datetime.datetime(2011, 1, 1, 0, 0)
timestamp2 may differ if midnight in the local timezone is not the same time instance as midnight in UTC.
mktime() may return a wrong result if
d corresponds to an ambiguous local time (e.g., during DST transition) or if
d is a past(future) date when the utc offset might have been different and the C
mktime() has no access to the tz database on the given platform. You could use
pytz module (e.g., via
tzlocal.get_localzone()) to get access to the tz database on all platforms. Also,
utcfromtimestamp() may fail and
mktime() may return non-POSIX timestamp if
"right" timezone is used.
datetime.date object that represents date in UTC without
DAY = 24*60*60 # POSIX day in seconds (exact value)timestamp = (utc_date.toordinal() - date(1970, 1, 1).toordinal()) * DAYtimestamp = (utc_date - date(1970, 1, 1)).days * DAY
How can I get a date converted to seconds since epoch according to UTC?
datetime.date) object that already represents time in UTC to the corresponding POSIX timestamp (a
from datetime import timezonetimestamp = dt.replace(tzinfo=timezone.utc).timestamp()
Note: It is necessary to supply
timezone.utc explicitly otherwise
.timestamp() assume that your naive datetime object is in local timezone.
Python 3 (< 3.3)
From the docs for
There is no method to obtain the timestamp from a datetime instance, but POSIX timestamp corresponding to a datetime instance dt can be easily calculated as follows. For a naive dt:
timestamp = (dt - datetime(1970, 1, 1)) / timedelta(seconds=1)
And for an aware dt:
timestamp = (dt - datetime(1970,1,1, tzinfo=timezone.utc)) / timedelta(seconds=1)
Interesting read: Epoch time vs. time of day on the difference between What time is it? and How many seconds have elapsed?
See also: datetime needs an "epoch" method
To adapt the above code for Python 2:
timestamp = (dt - datetime(1970, 1, 1)).total_seconds()
timedelta.total_seconds() is equivalent to
(td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / 10**6 computed with true division enabled.
from __future__ import divisionfrom datetime import datetime, timedeltadef totimestamp(dt, epoch=datetime(1970,1,1)): td = dt - epoch # return td.total_seconds() return (td.microseconds + (td.seconds + td.days * 86400) * 10**6) / 10**6 now = datetime.utcnow()print nowprint totimestamp(now)
Beware of floating-point issues.
How to convert an aware
datetime object to POSIX timestamp
assert dt.tzinfo is not None and dt.utcoffset() is not Nonetimestamp = dt.timestamp() # Python 3.3+
On Python 3:
from datetime import datetime, timedelta, timezoneepoch = datetime(1970, 1, 1, tzinfo=timezone.utc)timestamp = (dt - epoch) / timedelta(seconds=1)integer_timestamp = (dt - epoch) // timedelta(seconds=1)
On Python 2:
# utc time = local time - utc offsetutc_naive = dt.replace(tzinfo=None) - dt.utcoffset()timestamp = (utc_naive - datetime(1970, 1, 1)).total_seconds()
For unix systems only:
import datetime d = datetime.date(2011, 1, 1) d.strftime("%s") # <-- THIS IS THE CODE YOU WANT'1293832800'
Note 1: dizzyf observed that this applies localized timezones. Don't use in production.
Note 2: Jakub Narębski noted that this ignores timezone information even for offset-aware datetime (tested for Python 2.7).
Assumption 1: You're attempting to convert a date to a timestamp, however since a date covers a 24 hour period, there isn't a single timestamp that represents that date. I'll assume that you want to represent the timestamp of that date at midnight (00:00:00.000).
Assumption 2: The date you present is not associated with a particular time zone, however you want to determine the offset from a particular time zone (UTC). Without knowing the time zone the date is in, it isn't possible to calculate a timestamp for a specific time zone. I'll assume that you want to treat the date as if it is in the local system time zone.
First, you can convert the date instance into a tuple representing the various time components using the
dtt = d.timetuple() # time.struct_time(tm_year=2011, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=5, tm_yday=1, tm_isdst=-1)
You can then convert that into a timestamp using
ts = time.mktime(dtt) # 1293868800.0
You can verify this method by testing it with the epoch time itself (1970-01-01), in which case the function should return the timezone offset for the local time zone on that date:
d = datetime.date(1970,1,1)dtt = d.timetuple() # time.struct_time(tm_year=1970, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=3, tm_yday=1, tm_isdst=-1)ts = time.mktime(dtt) # 28800.0
28800.0 is 8 hours, which would be correct for the Pacific time zone (where I'm at).