converting epoch time with milliseconds to datetime converting epoch time with milliseconds to datetime python python

converting epoch time with milliseconds to datetime


Use datetime.datetime.fromtimestamp:

>>> import datetime>>> s = 1236472051807 / 1000.0>>> datetime.datetime.fromtimestamp(s).strftime('%Y-%m-%d %H:%M:%S.%f')'2009-03-08 09:27:31.807000'

%f directive is only supported by datetime.datetime.strftime, not by time.strftime.

UPDATE Alternative using %, str.format:

>>> import time>>> s, ms = divmod(1236472051807, 1000)  # (1236472051, 807)>>> '%s.%03d' % (time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)'2009-03-08 00:27:31.807'>>> '{}.{:03d}'.format(time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(s)), ms)'2009-03-08 00:27:31.807'


those are miliseconds, just divide them by 1000, since gmtime expects seconds ...

time.strftime('%Y-%m-%d %H:%M:%S', time.gmtime(1236472051807/1000.0))


I'm a pendulum fan... so...

import pendulumpendulum.from_timestamp(1236472051807/1000.0,tz='America/Toronto')

outputs:

DateTime(2019, 12, 20, 10, 55, 10, tzinfo=Timezone('America/Toronto'))

For all the searches looking for internalDate for the Gmail API... the above is what works for me and is more accurate than the Date header.