Copying a symbolic link in Python

Just do

def copy(src, dst):    if os.path.islink(src):        linkto = os.readlink(src)        os.symlink(linkto, dst)    else:        shutil.copy(src,dst)

shutil.copytree does something similar, but as senderle noted, it's picky about copying only directories, not single files.

Python 3 follow_symlinks

In Python 3, most copy methods of shutil have learned the follow_symlinks argument, which preserves symlinks if selected.

E.g. for shutil.copy:

shutil.copy(src, dest, follow_symlinks=False)

and the docs say:

shutil.copy(src, dst, *, follow_symlinks=True)

Copies the file src to the file or directory dst. src and dst should be strings. If dst specifies a directory, the file will be copied into dst using the base filename from src. Returns the path to the newly created file.

If follow_symlinks is false, and src is a symbolic link, dst will be created as a symbolic link. If follow_symlinks` is true and src is a symbolic link, dst will be a copy of the file src refers to.

This has one problem however: if you try to overwrite an existing file or symlink, it fails with:

FileExistsError: [Errno 17] File exists: 'b' -> 'c'

unlike the follow_symlinks=True which successfully overwrites.

The same also happens for os.symlink, so I ended up using instead:

#!/usr/bin/env python3import shutilimport osdef copy(src, dst):    if os.path.islink(src):        if os.path.lexists(dst):            os.unlink(dst)        linkto = os.readlink(src)        os.symlink(linkto, dst)    else:        shutil.copy(src, dst)if __name__ == '__main__':    os.symlink('c', 'b')    os.symlink('b', 'a')    copy('a', 'b')    with open('c', 'w') as f:        f.write('a')    with open('d', 'w'):        pass    copy('c', 'd')    copy('a', 'c')

Tested in Ubuntu 18.10, Python 3.6.7.