Django: Display Choice Value Django: Display Choice Value python python

Django: Display Choice Value

It looks like you were on the right track - get_FOO_display() is most certainly what you want:

In templates, you don't include () in the name of a method. Do the following:

{{ person.get_gender_display }}

For every field that has choices set, the object will have a get_FOO_display() method, where FOO is the name of the field. This method returns the “human-readable” value of the field.

In Views

person = Person.objects.filter(to_be_listed=True)context['gender'] = person.get_gender_display()

In Template

{{ person.get_gender_display }}

Documentation of get_FOO_display()

Others have pointed out that a get_FOO_display method is what you need.I'm using this:

def get_type(self):    return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]

which iterates over all of the choices that a particular item has until it finds the one that matches the items type