Double Progress Bar in Python

Use the nested progress bars feature of tqdm, an extremely low overhead, very customisable progress bar library:

$ pip install -U tqdm

Then:

from tqdm import tqdm# from tqdm.auto import tqdm  # notebook compatibleimport timefor i1 in tqdm(range(5)):    for i2 in tqdm(range(300), leave=False):        # do something, e.g. sleep        time.sleep(0.01)

(The leave=False is optional - needed to discard the nested bars upon completion.)

You can also use from tqdm import trange and then replace tqdm(range(...)) with trange(...). You can also get it working in a notebook.

I basically just want to add to the answer of @casper.dcl. In the slightly different case, where you have two nested for loops and want just a SINGLE progress bar you can do the following.

from tqdm import tqdmimport timen = 5m = 300with tqdm(total=n * m) as pbar:    for i1 in tqdm(range(n)):        for i2 in tqdm(range(m)):            # do something, e.g. sleep            time.sleep(0.01)            pbar.update(1)

I know that was not the question, but it might be still helpful for some folks.

It would require you to move the cursor position. I have written you a hacky thing to do it.

This script relies on the fact that the progressbar module assumes that you are on a fresh line to draw the progress bar. By simply moving the cursor up (using the escape code for "move cursor 1 row up"), and down (just using a newline. I could also use an escape code, but newline is easier and faster), one can maintain multiple progress bars.

import progressbar, time, sysdef up():    # My terminal breaks if we don't flush after the escape-code    sys.stdout.write('\x1b[1A')    sys.stdout.flush()def down():    # I could use '\x1b[1B' here, but newline is faster and easier    sys.stdout.write('\n')    sys.stdout.flush()# Total bar is at the bottom. Move down to draw itdown()total = progressbar.ProgressBar(maxval=50)total.start()for i in range(1,51):    # Move back up to prepare for sub-bar    up()    # I make a new sub-bar for every iteration, thinking it could be things    # like "File progress", with total being total file progress.    sub = progressbar.ProgressBar(maxval=50)    sub.start()    for y in range(51):        sub.update(y)        time.sleep(0.005)    sub.finish()    # Update total - The sub-bar printed a newline on finish, so we already    # have focus on it    total.update(i)total.finish()

This is of course a bit hacky, but it gets the job done. I hope that it is useful.