`elif` in list comprehension conditionals
Python's conditional expressions were designed exactly for this sort of use-case:
>>> l = [1, 2, 3, 4, 5]>>> ['yes' if v == 1 else 'no' if v == 2 else 'idle' for v in l]['yes', 'no', 'idle', 'idle', 'idle']
>>> d = {1: 'yes', 2: 'no'}>>> [d.get(x, 'idle') for x in l]['yes', 'no', 'idle', 'idle', 'idle']
You can, sort of.
Note that when you use sytax like:
['yes' if v == 1 else 'no' for v in l]You are using the ternary form of the if/else operator (if you're familiar with languages like C, this is like the ?: construct: (v == 1 ? 'yes' : 'no')).
The ternary form of the if/else operator doesn't have an 'elif' built in, but you can simulate it in the 'else' condition:
['yes' if v == 1 else 'no' if v == 2 else 'idle' for v in l]This is like saying:
for v in l: if v == 1 : print 'yes' else: if v == 2: print 'no' else: print 'idle'So there's no direct 'elif' construct like you asked about, but it can be simulated with nested if/else statements.