Embed bash in python

The ideal way to do it:

def run_script(script, stdin=None):    """Returns (stdout, stderr), raises error on non-zero return code"""    import subprocess    # Note: by using a list here (['bash', ...]) you avoid quoting issues, as the     # arguments are passed in exactly this order (spaces, quotes, and newlines won't    # cause problems):    proc = subprocess.Popen(['bash', '-c', script],        stdout=subprocess.PIPE, stderr=subprocess.PIPE,        stdin=subprocess.PIPE)    stdout, stderr = proc.communicate()    if proc.returncode:        raise ScriptException(proc.returncode, stdout, stderr, script)    return stdout, stderrclass ScriptException(Exception):    def __init__(self, returncode, stdout, stderr, script):        self.returncode = returncode        self.stdout = stdout        self.stderr = stderr        Exception().__init__('Error in script')

You might also add a nice __str__ method to ScriptException (you are sure to need it to debug your scripts) -- but I leave that to the reader.

If you don't use stdout=subprocess.PIPE etc, the script will be attached directly to the console. This is really handy if you have, for instance, a password prompt from ssh. So you might want to add flags to control whether you want to capture stdout, stderr, and stdin.

If you want to call system commands, use the subprocess module.

Is

import osos.system ("bash -c 'echo $0'")

going to do it for you?

EDIT: regarding readability

Yes, of course, you can have it more readable

import osscript = """echo $0ls -lecho done"""os.system("bash -c '%s'" % script)

EDIT2: regarding macros, no python does not go so far as far as i know, but between

import osdef sh(script):    os.system("bash -c '%s'" % script)sh("echo $0")sh("ls -l")sh("echo done")

and previous example, you basically get what you want (but you have to allow for a bit of dialectical limitations)