Extract files from zip without keeping the structure using python ZipFile?

This opens file handles of members of the zip archive, extracts the filename and copies it to a target file (that's how ZipFile.extract works, without taking care of subdirectories).

import osimport shutilimport zipfilemy_dir = r"D:\Download"my_zip = r"D:\Download\my_file.zip"with zipfile.ZipFile(my_zip) as zip_file:    for member in zip_file.namelist():        filename = os.path.basename(member)        # skip directories        if not filename:            continue            # copy file (taken from zipfile's extract)        source = zip_file.open(member)        target = open(os.path.join(my_dir, filename), "wb")        with source, target:            shutil.copyfileobj(source, target)

It is possible to iterate over the ZipFile.infolist(). On the returned ZipInfo objects you can then manipulate the filename to remove the directory part and finally extract it to a specified directory.

import globimport zipfileimport shutilimport osmy_dir = "D:\\Download\\"my_zip = "D:\\Download\\my_file.zip"with zipfile.ZipFile(my_zip) as zip:    for zip_info in zip.infolist():        if zip_info.filename[-1] == '/':            continue        zip_info.filename = os.path.basename(zip_info.filename)        zip.extract(zip_info, my_dir)

Just extract to bytes in memory,compute the filename, and write it there yourself,instead of letting the library do it - -mostly, just use the "read()" instead of "extract()" method:

Python 3.6+ update(2020) - the same code from the original answer, but using pathlib.Path, which ease file-path manipulation and other operations (like "write_bytes")

from pathlib import Pathimport zipfileimport osmy_dir = Path("D:\\Download\\")my_zip = my_dir / "my_file.zip"zip_file = zipfile.ZipFile(my_zip, 'r')for files in zip_file.namelist():    data = zip_file.read(files, my_dir)    myfile_path = my_dir / Path(files.filename).name    myfile_path.write_bytes(data)zip_file.close()

Original code in answer without pathlib:

import zipfileimport osmy_dir = "D:\\Download\\"my_zip = "D:\\Download\\my_file.zip"zip_file = zipfile.ZipFile(my_zip, 'r')for files in zip_file.namelist():    data = zip_file.read(files, my_dir)    # I am almost shure zip represents directory separator    # char as "/" regardless of OS, but I  don't have DOS or Windos here to test it    myfile_path = os.path.join(my_dir, files.split("/")[-1])    myfile = open(myfile_path, "wb")    myfile.write(data)    myfile.close()zip_file.close()